Golden Education

Quiz:   Fullscreen Mode Quiz 2: Fullscreen Mode Chemistry Energy Changes Or Chemical Energetics 🌡️ CHEMISTRY: ENERGY CHANGES 1. Exothermic & Endothermic Reactions Exothermic: Reaction that releases heat to surroundings → Temperature RISES → ΔH is NEGATIVE (ΔH Endothermic: Reaction that absorbs heat from surroundings → Temperature FALLS → ΔH is POSITIVE (ΔH > 0) Type Heat Flow Temperature ΔH Sign Examples Exothermic OUT ↗ RISES ↑ NEGATIVE (−) Combustion, respiration, neutralization Endothermic IN ↘ FALLS ↓ POSITIVE (+) Photosynthesis, thermal decomposition 2. Enthalpy Change (ΔH) Enthalpy Change (ΔH): Transfer of thermal energy during a reaction, measured in kilojoules (kJ) Main Formula: ΔH = Total energy of products − Total energy of reactants Example 1 (Exothermic): Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s) ΔH = −150 kJ (negative = heat released) Example 2 (...

Quiz 1:   Fullscreen Mode Other Quiz 🧪 METALS & REACTIVITY SERIES: Complete Theory & Formulas 🔬 I. FUNDAMENTAL THEORIES OF METALS 1.1 Electronic Theory of Metallic Bonding Sea of Electrons Model: Metals consist of a lattice of positive metal ions surrounded by a "sea" of delocalized electrons. This explains conductivity, malleability, and ductility. Metal Atom → Metal Ion⁺ + e⁻ M(s) → M⁺(aq) + e⁻ (general form) 1.2 Density Theory & Formula Density is a fundamental physical property that measures mass per unit volume. Density = Mass ÷ Volume ρ = m/V (g/cm³ or kg/m³) High Density Examples Gold: 19.3 g/cm³ Lead: 11.4 g/cm³ Copper: 8.9 g/cm³ ...

Quiz Other Quiz Using Moles - Complete Theory & Formulas Cambridge IGCSE Chemistry - Grade 9 1. The Mole Concept - Core Theory Definition of a Mole A mole is the amount of substance that contains as many elementary entities (atoms, molecules, ions) as there are atoms in exactly 12 grams of carbon-12 . Avogadro's Constant N A = 6.022 × 10 23 mol -1 This means 1 mole of any substance contains 6.022 × 10 23 particles Key Principle: One mole of any substance contains the same number of particles, but the mass depends on the type of particle. 2. Fundamental Formulas 2.1 Mole-Mass Relationship Number of moles (n) = Mass (m) ÷ Molar mass (M) n = m/M Mass (g...

Quiz 1:   Fullscreen Mode Quiz 2:   Fullscreen Mode Trigonometri, Peluang dan Statistik 📊 Rangkuman Rumus Matematika SMA Trigonometri, Peluang dan Statistik Oleh: Agus Salim 📈 1. STATISTIK Statistik adalah cabang matematika yang berkaitan dengan pengumpulan, analisis, interpretasi, presentasi, dan organisasi data. Dalam konteks SMA, fokus utama adalah pada ukuran pemusatan data dan ukuran penyebaran data. 🎯 1.1 Ukuran Pemusatan Data 📊 1.1.1 Rata-rata (Mean) a. Data Tunggal x̄ = (Jumlah semua nilai data) / (Banyaknya data) Keterangan: • x̄ = rata-rata • n = banyaknya data b. Data Kelompok x̄ = (Σ(fi × xi)) / (Σfi) Keterangan: • fi = frekuensi kelas ke-i • ...

Frequency Distribution Table - Sturges Method Frequency Distribution Table Generator Sturges Method Enter data values below (separated by semicolons). Maximum 500 values: Calculate Distribution Results New Calculation

Kalkulator Sudut Segitiga Kalkulator Sudut Segitiga Sisi a: Sisi b: Sisi c: Hitung Sudut Hasil Perhitungan Sudut A: derajat Sudut B: derajat Sudut C: derajat Penjelasan Hitung Ulang

Quiz 1:   Fullscreen Mode Gerak Parabola: Teori dan Rumus Lengkap Konsep Dasar Gerak Parabola Gerak parabola merupakan kombinasi dari gerak lurus beraturan (GLB) pada sumbu horizontal dan gerak lurus berubah beraturan (GLBB) pada sumbu vertikal. Fenomena ini terjadi ketika benda diberi kecepatan awal dengan sudut elevasi tertentu terhadap bidang horizontal. Persamaan Fundamental 1. Komponen Kecepatan Awal Kecepatan awal (v 0 ) dapat diurai menjadi: v 0x = v 0 · cosθ v 0y = v 0 · sinθ 2. Waktu Mencapai Titik Tertinggi t maks = (v 0 · sinθ)/g 3. Tinggi Maksimum (H) H = (v 0 2 · sin 2 θ)/(2g) 4. Jarak Jangkauan Maksimum (X) X = (v 0 2 · sin2θ)/g Contoh Soal dan Penyelesaian Sebuah bola dilempar dengan kecepatan awal 20 m/s dan sudut elevasi 37° (sin37°=0,6). Percepatan gravitasi 10 m/s². a. Komponen Kecepatan Awal v 0x = 20 · cos37° = 16 m/s v 0y = 20 · sin37° = 12 m/s b. Kecepatan pada t=0,4s v x = 16 m/s (konstan) v y = ...